Posted by Jon on .
Find the exact solutions to 6x^2+x+4=0 by using the quadratic formula.
x=b+sqrtb^24ac/2a
1+sqrt1^24(6)(4)/2(6)
1+sqrt95/12
195/12
96/12
x= 8
1+95/12
94/12= 7.8333..
[8, 7.83](answer)

Algebra II 
mktintin,
do u cumplex numbers???

Algebra II 
Jon,
What do you mean?

Algebra II 
mktintin,
do u know cumplex numbers???as your sqrt is negative(b²4ac=95) you have to use cumplex numbers to solve this equation

Algebra II 
Jon,
no that's the only way I know how to do it.

Algebra II 
mktintin,
so 6x²+x+4=0 has no one solution(no one real solution but there are cumplex solution : it's (1+isqrt95)/12

Algebra II 
Doc of MH,
since a=6,b=1,c=4
=B¡¾¡î(B©÷4AC)/2A
"1¡¾¡î(1©÷4(6)(4))/2(6)
"1¡¾¡î(95)/12
so the roots are imaginary
"since the square root of "1" is "I"
(yes the letter "I")
Then your roots are
"(1+9.74i)/12 and (19.74i)/12