Posted by **Jon** on Saturday, March 1, 2008 at 8:03pm.

Find the exact solutions to 6x^2+x+4=0 by using the quadratic formula.

x=-b+-sqrtb^2-4ac/2a

-1+-sqrt1^2-4(6)(4)/2(6)

-1+-sqrt-95/12

-1-95/12

-96/12

x= -8

-1+95/12

94/12= 7.8333..

[-8, 7.83](answer)

- Algebra II -
**mk-tintin**, Saturday, March 1, 2008 at 8:08pm
do u cumplex numbers???

- Algebra II -
**Jon**, Saturday, March 1, 2008 at 8:13pm
What do you mean?

- Algebra II -
**mk-tintin**, Saturday, March 1, 2008 at 8:15pm
do u know cumplex numbers???as your sqrt is negative(b²-4ac=-95) you have to use cumplex numbers to solve this equation

- Algebra II -
**Jon**, Saturday, March 1, 2008 at 8:21pm
no thats the only way I know how to do it.

- Algebra II -
**mk-tintin**, Saturday, March 1, 2008 at 8:31pm
so 6x²+x+4=0 has no one solution(no one real solution but there are cumplex solution : it's (-1+-isqrt95)/12

- Algebra II -
**Doc of MH**, Thursday, May 8, 2008 at 11:47am
since a=6,b=1,c=4

=-B¡¾¡î(B©÷-4AC)/2A

"-1¡¾¡î(1©÷-4(6)(4))/2(6)

"-1¡¾¡î(-95)/12

so the roots are imaginary

"since the square root of "-1" is "I"

(yes the letter "I")

Then your roots are

"(-1+9.74i)/12 and (-1-9.74i)/12

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