Posted by Jon on Saturday, March 1, 2008 at 8:03pm.
do u cumplex numbers???
What do you mean?
do u know cumplex numbers???as your sqrt is negative(b²-4ac=-95) you have to use cumplex numbers to solve this equation
no thats the only way I know how to do it.
so 6x²+x+4=0 has no one solution(no one real solution but there are cumplex solution : it's (-1+-isqrt95)/12
since a=6,b=1,c=4
=-B¡¾¡î(B©÷-4AC)/2A
"-1¡¾¡î(1©÷-4(6)(4))/2(6)
"-1¡¾¡î(-95)/12
so the roots are imaginary
"since the square root of "-1" is "I"
(yes the letter "I")
Then your roots are
"(-1+9.74i)/12 and (-1-9.74i)/12
since a=6,b=1,c=4
=-B¡¾¡î(B©÷-4AC)/2A
"-1¡¾¡î(1©÷-4(6)(4))/2(6)
"-1¡¾¡î(-95)/12
so the roots are imaginary
"since the square root of "-1" is "I"
(yes the letter "I")
Then your roots are
"(-1+9.74i)/12 and (-1-9.74i)/12
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