Posted by Jon on .
Write a quadratic equation with 3/4 and 4 as its roots. Write the equation in form ax^2+bx+c=0, where a,b,and c are integers.
(xp)(xq)=0
(x3/4)(x4)=0
(x+3/4)(x4)=0
x^23x+3=0(answer)

Algebra II 
mktintin,
(x+3/4)(x4)=x²+3/4x4x3=x²(13/4)x3
if u want to know if your answer is right or false, it's easy
f(x)=x²(13/4)x3
and u can verify if f(4)=0 and f(3/4)=0 
Algebra II 
Reiny,
if the roots are 3/4 and 4 then the factors that will form your equation are
(4x+3) and (x4)
so (4x+3)(x4) = 0 or
4x^2 13x  12 = 0