Algebra II
posted by Lucy .
Simplify:
4xy^3/z^2 divided by (8x^2y/z^3)^2
I came up with the following:
2.2.x.y.y.y.z.z.z.z.z/z.z.z2.2.16.x.x.x.x.y.y
Simplified into x^3y/16x^3.
Is this correct?
Thanks for your help earlier and now.

No. x^3*y/16 = y/16, and that is not the answer.
You've got a (1/z^2) divided by a (1/z^6), which should be z^4, yet you have no "z" term in your answer.
Try writing it as
4x*y^3*z^6/(z^2*64*x^4*y^2)
and then canceling terms.