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September 16, 2014

September 16, 2014

Posted by **Jon** on Saturday, March 1, 2008 at 1:19pm.

- Algebra II -
**Reiny**, Saturday, March 1, 2008 at 1:31pmYou probably meant h(x)= -0.03x^2+3x

several ways to do this

1. by Calculus, find derivative, set it equal to zero and solve

2. by completing the square and changing the equation to the standard form of a parabola

3. in this case this is the easiest way:

since it factors to

h(x)= x(-0.03x+3)

and when h(x) = 0, x = 0 or -.03x+3=0

yielding x = 100

so the x-intercept of this parabola are 0 and 100, which means that the vertex is at the midway, or at x=50

so h(50) = 75

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