Posted by rory on Saturday, March 1, 2008 at 12:38pm.
Divide the energy acquired at the top of the hill (kinetic PLUS potential) buy the leapsed time (15.7 s). Energy divided by time equals power.
P = [(1/2)MV^2 + M g H]/15.7 s
g = 9.8 m/s^2
H = 49.0 m
Divide the energy acquired at the top of the hill (kinetic PLUS potential) by the elapsed time (15.7 s). Energy divided by time equals power.
P = [(1/2)MV^2 + M g H]/15.7 s
g = 9.8 m/s^2
H = 49.0 m
M = 690 kg
V = 24.9 m/s
P = (213,900 + 34,290)/15.7 = 18,808 W = 21 horsepower
Check my thinking and numnbers.
yeah the only thing you did wrong was the final answer it should be 34.72E3 W
I did the MgH term wrong, and agree with your answer.
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