Wednesday
July 23, 2014

Homework Help: algebra

Posted by frank on Saturday, March 1, 2008 at 10:34am.

You may have to convert from feet to miles several times in this assignment. You can use 1 mile = 5,280 feet for your conversions.
1.Many people know that the weight of an object varies on different planets, but did you know that the weight of an object on earth also varies according to the elevation of the object? In particular, the weight of an object follows this equation: , where C is a constant, and r is the distance that the object is from the center of the earth.
a. Solve w=Cr^-2the equation for r.
My Answer: r = sqrt(C/w)
b. Suppose that an object is 100 pounds when it is at sea level. Find the value of C that makes the equation true. (Sea level is 3,963 miles from the center of the earth.)
My answer: C = 1,570,536,900
c. Use the value of C you found in the previous question to determine how much the object would weigh in
i. Death Valley (282 feet below sea level)
My answer: w = 100.15 pounds
ii. The top of Mt McKinley (20,430 feet above sea level)
My Answer: w = 99.96 pounds
2. The equation D=1.2(sqrt)h which should read D equals 1.2 square root of h gives the distance, D, in miles that a person can see to the horizon from a height, h, in feet.
a. Solve this equation for h.
My Answer: (D / 1.2)^2 = h
b. Long’s Peak in the Rocky Mountain National Park, is 14,255 feet in elevation. How far can you see to the horizon from the top of Long’s Peak? Can you see Cheyenne, Wyoming (about 89 miles away)? Explain your answer.
My Answer: A person can see 143.27 miles from the top and yes you can see Cheyenne because 89 is less than 143.

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