Saturday

December 20, 2014

December 20, 2014

Posted by **Jon** on Saturday, March 1, 2008 at 9:48am.

2+i/1-3i

= 2+i/1-3i

= (2+i/1-3i) * (1+3i/1+3i)

= (2+3i^2)/(1-9i^2)

= (2/1) - (1/3i)

= 2-1/3i(answer)

- Algebra II (check) -
**Reiny**, Saturday, March 1, 2008 at 10:11amno.... from your

(2+i/1-3i) * (1+3i/1+3i)

= (2+i)/(1-3i) * (1+3i)/(1+3i)

= (2 + 6i + i - 3i^2)/(1 - 9i^2) remember i^2 = -1

= (5+7i)/10

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