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March 24, 2017

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Assume that no denominator equals 0.

2+i/1-3i

= 2+i/1-3i
= (2+i/1-3i) * (1+3i/1+3i)
= (2+3i^2)/(1-9i^2)
= (2/1) - (1/3i)
= 2-1/3i(answer)

  • Algebra II (check) - ,

    no.... from your

    (2+i/1-3i) * (1+3i/1+3i)
    = (2+i)/(1-3i) * (1+3i)/(1+3i)

    = (2 + 6i + i - 3i^2)/(1 - 9i^2) remember i^2 = -1

    = (5+7i)/10

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