Posted by Jon on Friday, February 29, 2008 at 6:53pm.
Assume that no denomenator equals 0.
(7x^2+3x9)(x^2+8x3)
= 7x^2+3x9+x^28x+3
= (7x^2+x^2)+(3x8x)+(9+3)
= 8x^2+5x+6
= 8x^25x6(answer)

Algebra II  Dan, Friday, February 29, 2008 at 7:00pm
What exactly is your question? I don't even see a denominator anywhere :)
What you have is right so far. If you want to finish that question you need to use the quadratic formula
x = (b +/ square root(b^2  4ac)) / 2a
x = (5 +/ square root (25 + 192)) / 16
x = (5 +/ square root (217)) / 16
which yields x1 = 1.23 and x2 = 0.61 
Algebra II  Jon, Friday, February 29, 2008 at 7:11pm
(7x^2+3x9)(x^2+8x3) is the question. the rest is my work

Algebra II  Dan, Friday, February 29, 2008 at 7:13pm
Your solution is perfect, did you just want confirmation?

Algebra II  Jon, Friday, February 29, 2008 at 7:17pm
yes