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September 18, 2014

September 18, 2014

Posted by **Anonymous** on Friday, February 29, 2008 at 1:36pm.

a)60% in the body on the right-hand side

b)90% in the body on the left-hand side

- statistics -
**drwls**, Friday, February 29, 2008 at 3:35pm60% is to the right of z = -0.25

90% is to the left of z = +1.28

"z" is (x-x(mean))/{standard deviation)

You need a table of the error function or normal distribution to do this kind of problem.

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