why can't a right triangle have decimals in the other two angles?
it has a right angle, therefor the other two must add up to equal 180, correct?
well i did my calculations, and i got 53.6 degrees for angle 1 and for angle 2, 36.4 degrees. they all add up to equal 180. why did the teacher take off 2 points off because i had decimals in the answer?
Did you teacher actually say that's why you lost 2 marks? It might have been lack of decimal place(s) or an incorrect answer.
Triangles can definitely have decimal angles.
it said find the missing values (tenth), so doesn't that mean you round to the nearest tenth decimal place?
First of all the other two angles of a right-angled triangle add up to 90º, not 180º.
Of course the other two angles can have decimals, they could even be irrational
Suppose one angle is √450º, then the other angle would be (90-√450)º
As long as they are both positive, they can be any two real numbers, as long as they add up to 90
I got decimals in my answer for a problem, so yeah... I think you can have decimals.
man, i got decimals too! anybody? just saying, i think it is theoretically possible to have a decimal in an angle.
Well, it sounds like your teacher might not have been a fan of triangular d
In a right triangle, one angle is always 90 degrees. The sum of the other two angles must be 90 degrees for the triangle to be a right triangle. So, if you have calculated angles that add up to 180 degrees but include decimals, it indicates that there may be an error in your calculation.
To clarify, let's calculate the angles of a right triangle using the Pythagorean theorem. Suppose we have a right triangle with side lengths A, B, and C (where C is the hypotenuse). According to the Pythagorean theorem, A^2 + B^2 = C^2.
Let's assume that A = 6 and B = 8. To find angle 1, we can use the inverse tangent function (tan^-1) of A/B. Angle 1 = tan^-1(6/8) = tan^-1(0.75) = 36.87 degrees.
Angle 2 can be calculated by using the inverse sine function (sin^-1) of A/C. Angle 2 = sin^-1(6/C). To find C, we can use the Pythagorean theorem, C^2 = A^2 + B^2. C = sqrt(6^2 + 8^2) = sqrt(100) = 10. Angle 2 = sin^-1(6/10) = sin^-1(0.6) = 36.87 degrees.
As you can see, both angle 1 and angle 2 are equal and measure approximately 36.87 degrees. They add up to a total of 73.74 degrees, which is less than 90 degrees. So, there was an error in your calculation.
It is important to use accurate calculations and avoid rounding errors when working with triangles. Decimals in the angles of a right triangle indicate that the triangle may not be a right triangle, which is why your teacher may have deducted points.