Samples of neon and helim are placed into separate containers connected by a pniched rubber tube as shown. When the clamp is removed and the gases are allowed to mix, what is the final pressure of the neon? The volume of the tube is negligible. 5.00L, 654 mmHg is Neon. 3.00L,522mmHG helium. Can anyone pleaase help me figure out how to get the answer. The answer is 409 mm Hg. Thanks:)

WHat? I don't understand???

To solve this problem, we need to apply the principles of partial pressure and combine the pressure and volume of the two gases.

First, let's list the given information:
- The initial volume of neon (V1) is 5.00L, and its initial pressure (P1) is 654 mmHg.
- The initial volume of helium (V2) is 3.00L, and its initial pressure (P2) is 522 mmHg.

Now, let's calculate the final pressure (Pf) of neon after the two gases have mixed.

1. Convert the pressure values into a common unit (mmHg or atm) if necessary:
- Since both given pressures are in mmHg, no conversion is needed.

2. Combine the pressures of the two gases using Dalton's law of partial pressure:
- According to Dalton's law, the total pressure (Pt) is the sum of the partial pressures of each gas.
- Pt = P1 + P2

Pt = 654 mmHg + 522 mmHg
Pt = 1176 mmHg

3. To find the final pressure of neon (Pf), we need to determine its partial pressure in the mixture. Since the volume of the tube is considered negligible, we can assume that the gases will mix evenly. This means that the ratio of the partial pressure of neon to the total pressure of the mixture will be the same as the ratio of the initial volume of neon to the total initial volume.

Pf/Pt = V1/(V1 + V2)

Pf/1176 mmHg = 5.00L/(5.00L + 3.00L)
Pf/1176 mmHg = 5.00L/8.00L

Cross-multiply and solve for Pf:

8.00L × Pf = 1176 mmHg × 5.00L
8.00L × Pf = 5880 mmHg * L

Pf = 5880 mmHg * L / 8.00L
Pf = 735 mmHg

The final pressure of neon (Pf) is 735 mmHg.

However, the given answer is 409 mmHg, which is different from our calculation. It's possible that there is a mistake in the given information or that the calculations were not performed correctly. Please double-check the original question or consult with a teacher or tutor for clarification.

I would use P1V1 = P2V2 converting pressure Ne at 5.00 L to Ne at 8.00 L. Do the reverse for He. Then add the two partial pressurs to obtain the final pressure.

I gave you more information than you needed. Do what I recommended for the Ne. the problem doesn't ask for total pressure; therefore, you don't need to calculate the He pressure nor do you need to add them.