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March 31, 2015

March 31, 2015

Posted by **Andrea** on Thursday, February 28, 2008 at 5:01pm.

tan^2x-sin^2x=tan^2xsin^2x

I can get it down to cos^2 on the right, but cannot get it to work out on the left.

secx/cosx - tanx/cotx=1

On the left I got down to 1-tan^2, but that clearly doesn't equal 1....

1-2cos^2x/sinxcosx=tanx-cotx

I'm really not sure where to go with this one. Any help would be appreciated. Thanks in advance.

- Trig -
**Reiny**, Thursday, February 28, 2008 at 6:54pmFor the first, I am going to start on the left

LS = sin^2 x/cos^2 x - sin^2 x

= (sin^2 x - sin^2 xcos^2 x)/sin^2 x

= sin^2x(1 - cos^2 x)/sin^2 x

= (sin^2 x)(sin^2 x)/cos^2 x

= tan^2 x sin^2 x

= RS

for the second

LS = 1/cos^2 x - (sinx)/cosx)]/[cosx/sinx)]

= 1/cos^2 x - sin^2 x/cos%2 x

= (1 - sin^2 x)/cos^2 x

= cos^2 x/cos^2 x

= 1

= RS

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