Posted by LILY on Wednesday, February 27, 2008 at 3:10pm.
a) The "airspeed" vector has a magnitude of 400 km/h and a direction in which the pilot points the plane (which is what they are asking you to calculate). The wind velocity vector has magnitude 60 km/h and direction TOWARD the west. The ground velocity vector of the plane going to Piitsburgh has a direction due south. It is the sum of the airspeed and windspeed vectors. You have two sides and one angle of the vector-addition triangle, so can solve for all unknowns.
b) Get the ground speed of the Pittsburhg leg of the trip from the vector triangle opf the last problem. Divide 350 km by that speed for the elapsed time. For the leg of the trip to Philly, the ground speed is just 400 - 60 = 340 km/h. Compute the elapsed time for that leg, and add the first leg elapsed time plus 0.5 hours.
c) Compute the travel time for the direct flight using the same method to get the ground velocity vector. You know its direction already. Compare that to the answer in (b) to get the required waiting time before takeoff.
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