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December 22, 2014

December 22, 2014

Posted by **sarah** on Tuesday, February 26, 2008 at 11:10pm.

the sum from k=1 to infinity of

cos(e^-k)

I'm not sure where to start..

- calculus -
**drwls**, Wednesday, February 27, 2008 at 12:42amAs k becomes very large, e^-k approaches zero, and every cos(e^-k) term approaches 1.

You end up with an infinite series of terms all approaching +1, which cannot converge

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