Wednesday

November 26, 2014

November 26, 2014

Posted by **sarah** on Tuesday, February 26, 2008 at 11:08pm.

the sum from k=1 to infinity of

sin(e^-k)

I'm not sure where to start..

- calculus -
**drwls**, Wednesday, February 27, 2008 at 3:06amAs k becomes large, e^-k becomes much less than 1, and sin(e^-k) approaches e^-k

The sum of the series 1 + 1/e + 1/e^2 converges to

1 /(1 - 1/e)= 1.582

High-order terms of the series

sin(e^-k) will behave similarly, but the sum of the entire series will be somethat less than 1.582.

**Answer this Question**

**Related Questions**

calculus - determine whether the series converges of diverges the sum from k=1 ...

calculus - determine whether the series converges of diverges the sum from n=1 ...

calculus - determine whether the series converges of diverges the sum from k=1 ...

calculus - determine whether the series converges of diverges the sum from k=2 ...

calculus - determine whether the series converges of diverges the sum from k=2 ...

Calculus - The problem with these two questions is that I cannot determine the a...

calculus - 1. integral -oo, oo [(2x)/(x^2+1)^2] dx 2. integral 0, pi/2 cot(theta...

calculus - determine whether the series converges of diverges the sum from n=1 ...

calculus - determine whether the series converges of diverges the sum from n=1 ...

Calculus - Determine the following about the series. Indicate the test that was ...