Posted by **Anna** on Tuesday, February 26, 2008 at 10:02pm.

The diagonals of a rhombus have lenghts 16 and 30. Find the perimeter of the rhombus.

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**drwls**, Tuesday, February 26, 2008 at 10:15pm
The sides, which are equal since it is a rhombus, have a length dimension of sqrt (8^2 + 15^2) = sqrt(289) = 17, because the diagonals are perpendicular. The perimeter is therefore 4x17 = 68

- math -
**drwls**, Wednesday, February 27, 2008 at 10:23am
I am applying the Pythagorean theorem

a^2 + b^2 = c^2

c is the length of a side

a and b are half the lengths of the two diagonals. Draw yourself a picture with intersetinc diagonals and you will see the four congruent right triangles. Make sure you do it for a rhombus, which is a parallelogram with all sides equal.

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