How to solve the two formulas for x+y=21 3x+4y=21
you can use a substraction-or-addition method or substitude method.
So...
x+y=21 you multiply both side by 3 3x+3y=63
3x+4y=21
---------
then you eliminate one variable
you use the subtraction method
-y=42
y=-42
then you solve for x by substituting the y
x+(-42)=21
x=63
i need to know how to turn 48.25 into a fration in simpilist forn
48.25 =4825/100 = 193/4 = 48 1/4
or just realize that .25 = 1/4
so 48.25 = 48 1/4
Please don't post a question as part of a previous thread, start a new topic
That way you will have a much better chance at a tutor looking at it.
48.25 =4825/100 = 193/4 = 48 1/4
or just realize that .25 = 1/4
so 48.25 = 48 1/4
Please don't post a question as part of a previous thread, start a new topic
That way you will have a much better chance at a tutor looking at it.
To solve the system of equations:
x + y = 21 ----(1)
3x + 4y = 21 ----(2)
There are several methods you can use, but I'll explain the substitution method.
Step 1: Solve one of the equations for either x or y in terms of the other variable.
Let's solve equation (1) for x:
x = 21 - y
Step 2: Substitute the expression for x into the other equation.
Substitute x = 21 - y into equation (2):
3(21 - y) + 4y = 21
Step 3: Simplify and solve for y.
Expand and solve the equation:
63 - 3y + 4y = 21
Combining like terms:
63 + y = 21
Subtract 63 from both sides:
y = 21 - 63
y = -42
Step 4: Substitute the found value of y back into one of the original equations and solve for x.
Using equation (1):
x + (-42) = 21
x - 42 = 21
Add 42 to both sides:
x = 21 + 42
x = 63
So, the solution to the system of equations is x = 63 and y = -42.