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November 29, 2014

November 29, 2014

Posted by **Kaushik** on Tuesday, February 26, 2008 at 8:59pm.

List all the answers please.

- Math -
**drwls**, Wednesday, February 27, 2008 at 8:35amBreak 120 up into a product of prime numbers. Then break that list into as many combinations of three numbers as you can think of, using all of the numbers. Examples:

120 = 1*2*2*2*3*5

= 1*(2*2*2)*(3*5)= 1x8x15

= 2*(2*2)*(3*5)= 2x4x15

= 1*2*(2*2*3*5)=1x2x60

= (2*2)(2*3)*5= 4x6x5

= 2*(2*5)*(2*3)=2x10x6

etc

- Math -
**sophia**, Thursday, February 28, 2008 at 1:02am4x + 10 -3x =2-3

- Math -
- Math -
**Reiny**, Wednesday, February 27, 2008 at 8:54am120 = 2*2*2*3*5

So we need triples of these that multiply to get 120, but we must not forget that 1 can also be used.

So I went about it sort of systematically

1,1,120 ----- only case with 2 ones

1,2,60

1,3,40

1,4,30

1,5,24

1,6,20

1,8,15

1,10,12 --- to got more would repeat some

2,2,30

2,3,20

2,4,15

2,5,12

2,6,10

4,3,10

4,5,6

8,3,5

Done, 16 of them

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