Friday

October 24, 2014

October 24, 2014

Posted by **sarah** on Tuesday, February 26, 2008 at 8:36pm.

the sum from n=1 to infinity of

1/(the square root of (n^3+1))

I said that through the comparision test (comparing to 1/the square root of (n^3) the series converges

is this true?

- calculus -
**Damon**, Tuesday, February 26, 2008 at 8:39pmThat is a valid way to do it. Yes, every term is smaller than 1/n^3

**Answer this Question**

**Related Questions**

calculus - determine whether the series converges of diverges the sum from n=1 ...

calculus - determine whether the series converges of diverges the sum from k=2 ...

calculus - determine whether the series converges of diverges the sum from k=2 ...

calculus - determine whether the series converges of diverges the sum from k=1 ...

calculus - determine whether the series converges of diverges the sum from k=1 ...

calculus - determine whether the series converges of diverges the sum from k=1 ...

calculus - determine whether the series converges of diverges the sum from n=1 ...

Calculus - The problem with these two questions is that I cannot determine the a...

calculus - true or false: if the sum from n=1 to infinity of a(n) converges, and...

Calculus - Determine the following about the series. Indicate the test that was ...