calculus
posted by sarah on .
determine whether the series converges of diverges
the sum from n=1 to infinity of
1/(the square root of (n^3+1))
I said that through the comparision test (comparing to 1/the square root of (n^3) the series converges
is this true?

That is a valid way to do it. Yes, every term is smaller than 1/n^3