determine whether the series converges of diverges
the sum from n=1 to infinity of
1/(the square root of (n^3+1))
I said that through the comparision test (comparing to 1/the square root of (n^3) the series converges
is this true?
calculus - Damon, Tuesday, February 26, 2008 at 8:39pm
That is a valid way to do it. Yes, every term is smaller than 1/n^3