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November 28, 2014

November 28, 2014

Posted by **sarah** on Tuesday, February 26, 2008 at 8:36pm.

the sum from n=1 to infinity of

1/(the square root of (n^3+1))

I said that through the comparision test (comparing to 1/the square root of (n^3) the series converges

is this true?

- calculus -
**Damon**, Tuesday, February 26, 2008 at 8:39pmThat is a valid way to do it. Yes, every term is smaller than 1/n^3

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