Posted by **Anonymous** on Tuesday, February 26, 2008 at 7:17pm.

A 3.5 kg object is suspended from a spring of spring constant 725 N/m. Starting from the equilibrium position, the object has an initial speed of 7.9 m/s. What is the maximum displacement of the object during its subsequent motion? (In cm)

- Physics -
**Damon**, Tuesday, February 26, 2008 at 7:28pm
Kinetic energy at start = (1/2) m v^2

= (1/2)(3.5)(7.9)^2

= 109 Joules

At the maximum displacement, it stops, so that kinetic energy has all gone into stretching the spring which stores it as potential energy

Potential energy in spring = (1/2) k x^2

so

(1/2) ( 725) * x^2 = 109 Joules

x^2 = .301

x = .549 meters

= 55 cm

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