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March 4, 2015

March 4, 2015

Posted by **Mischa** on Tuesday, February 26, 2008 at 6:28pm.

(I have no idea how that would even work)

- statistics -
**Reiny**, Tuesday, February 26, 2008 at 6:54pmthrowing 2 dice and flipping a coin.

suppose you want the prob(heads and a sum of 7)

the process of flipping the coin has no effect on the act of throwing the dice.

Thus the events are "independent"

- statistics(ignore my answer) -
**Reiny**, Tuesday, February 26, 2008 at 7:00pmsorry I misread your question

- statistics(ignore my answer) -
- statistics -
**Damon**, Tuesday, February 26, 2008 at 7:09pmIf the sets are not disjoint then they have elements in common.

for example

the set A containing numbers 1 through 7. There is only one of each number in the set.I can only pick from set A

and

the set B containing numbers 6 through 9. There is only one of each number in the set. You can only pick from set B

Is the probability of picking a number from set B changed by the previous random selection of a number from box A?

Sure it is. If I took the six or the seven from set A, I took it from the intersection, and you can not pick it. Therefore the events are not independent.

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