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February 1, 2015

February 1, 2015

Posted by **Mackenzie** on Tuesday, February 26, 2008 at 3:55pm.

a. how many sequences are possible for the last 4 digits?

b. what is the probability of getting 5 or 0 in the last digit.

c. what is the probability of getting two 5's in the last two digits?

- math -
**drwls**, Tuesday, February 26, 2008 at 5:44pma.) 0000 through 9999 = 10,000 possibilities

b.) 1/10 + 1/10 = 1/5

c.) 1 (55) out of 100 (00 through 99)

- math -
**Mackenzie**, Tuesday, February 26, 2008 at 7:30pmfor a i thought you were supposed to do 9*8*7*6 and the answer that i got was 3,024.

for b i got 9*8=72

for c i got 9*9=81

does that make sense

- math -
**PsyDAG**, Wednesday, February 27, 2008 at 11:12amThe numerals get smaller if you are considering probabilities

*without replacement*. In other words, using a numeral in one position would prohibit its use in other positions. However, the use of any numeral does not effect the probabilities of the remaining numerals.

I hope this helps a little more. Thanks for asking.

- math -

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