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April 18, 2014

April 18, 2014

Posted by **rick** on Tuesday, February 26, 2008 at 1:24pm.

- trig -
**^Quen^**, Tuesday, February 26, 2008 at 8:46pmcos(A-B)= cosAcosB+sinAsinB

If sinA = 4/5 in QII

draw you triangle in QII, and find the third side.

The third side is 3. (Do the same thing for sin B= -3/5

Plug in:

cosAcosB-sinAsinB

=(-3/5)*(4/5)+(4/5)*(-3/5)

=(-12/25) -(-12/25)

=-24/25

- trig -
**Anonymous**, Tuesday, September 11, 2012 at 7:59pm53. the longest side is 55 cm. find the length of the shortest side

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