Posted by Jon on Tuesday, February 26, 2008 at 2:25am.
(This is the info for the question NOT the actual question)
A furniture company displays bedroom sets which require 21 square meters of space and living room sets which require 42 square meters of space. The company, which has 546 square meters of avalible space, wants to display at least 6 bedroom sets and at least 5 living room sets.
Question:
If a bedroom set sells for $10,000 and a living room set sells for $18,000, determine the number of bedroom sets and living room sets that must be sold to maximize the amount collected.
16 beds * 21 square meters of space = 336
5 living * 42 square meters of space = 210
add those two up and get the total availible space of 546
16 * 10,000 = $160,000
5 * $18,000 = $90,000
= $250,000 maxed out
So they would need to sell 16 bedroom sets and 5 living room sets

Algebra  drwls, Tuesday, February 26, 2008 at 7:18am
You seem to have answered the question. The method is to realize that bedroom sets sell for more per floor area; therefore, once the required minimum number of living room sets(5)is displayed, to use all remaining space for bedroom sets. There is room for 16.

Algebra  Kathryn, Monday, June 28, 2010 at 11:29pm
draw the graph showing the feasible region. Label the coordinates of the vertices of the feasible region.
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