Posted by **Sam** on Tuesday, February 26, 2008 at 1:54am.

If a student is chosen at random, find the probability of getting someone who is a man or a non-smoker. Round your answer to three decimal places.

non regular heavy total

man 135 64 5 204

women 187 21 9 217

total 322 85 14 421

Answer in decimal (round to nearest 3)

Please help me, I've taken more than an hour to figure this problem out! Please guys! Really appreciate it.

- Statistics / Math -
**drwls**, Tuesday, February 26, 2008 at 2:10am
Out of a total of 421 people, of both sexes and three classifications of smoking habits, 135 were nonsmoking men. Therefore the probability is 135/421 = 0.3207

This assumes that the sampling group was representative of the larger group of people they may have been drawn from.

- Statistics / Math -
**drwls**, Tuesday, February 26, 2008 at 6:08am
I misread the problem as man AND nonsmoker. You want man OR nonsmoker. Using the same method but more groups from the table, I get

(204 + 187)/421 = 0.929

- Statistics / Math -
**lorri**, Monday, April 7, 2014 at 12:41am
Calculate the standard deviation for: 10, 20, 30 to the nearest tenth presuming a sample

## Answer This Question

## Related Questions

- Statistics / Math - If a student is chosen at random, find the probability of ...
- statistics - Question: The table below shows the drinking habits of adult men ...
- statistics - A person is selected at random from a population that has the ...
- statistics - Question: The table below shows the drinking habits of adult men ...
- Math - Four hundred people apply for three jobs. 130 of the applicants are women...
- math - i have no clue how to do this problem. any help would be appreciated...
- Math - Three hundred people apply for three jobs. 80 of the applicants are women...
- statistics - Among 17 metal parts produced in a machine shop, 6 are defective. ...
- Statistics - If one of the 467 men is randomly selected, what is the probability...
- Statistics - The probability that a student uses the Academic Resource Center on...

More Related Questions