BrO-3 + 5Br- + 6H+ ---> 3Br2 + 3H2O the value of - delta[BrO3]/delta T= 1.5x10^-2M/s at a particular time what is the value of -delta [Br-]/Delta t at the same instant?
13 M/s
7.5x10^-2
1.5x10^-2
3.0x10^-2
330 M/s
7.5x10^-2
To find the value of -delta [Br-]/Delta t at the same instant, we need to understand the stoichiometry of the reaction and the relationship between the rate of change of different species.
The balanced equation shows that for every molecule of BrO3- consumed, 5 molecules of Br- are consumed. Therefore, the stoichiometric ratio of -delta [Br-]/Delta t to -delta [BrO3]/Delta t is 5:1.
Since the given value of -delta [BrO3]/Delta t is 1.5x10^-2 M/s, we can use this value to calculate the value of -delta [Br-]/Delta t.
- delta [BrO3]/delta t = 1.5x10^-2 M/s
- delta [Br-]/delta t = (5x1.5x10^-2) M/s
- delta [Br-]/delta t = 7.5x10^-2 M/s
Therefore, the value of -delta [Br-]/Delta t at the same instant is 7.5x10^-2 M/s.
To find the value of -delta [Br-]/delta t at the same instant, we need to use the stoichiometry of the balanced chemical equation.
From the balanced equation:
1 mol of BrO-3 reacts with 5 mol of Br-
This means that for each mole of BrO-3 that disappears, 5 moles of Br- are consumed.
The rate of reaction for BrO-3 can be given as:
-delta [BrO-3]/delta t = 1.5x10^-2 M/s
Using the stoichiometry, we can calculate the rate of change of Br-:
-delta [Br-]/delta t = (1/5) * (-delta [BrO-3]/delta t)
= (1/5) * (1.5x10^-2 M/s)
= 3x10^-3 M/s
Therefore, the value of -delta [Br-]/delta t at the same instant is 3x10^-3 M/s.