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March 2, 2015

March 2, 2015

Posted by **chelsea** on Monday, February 25, 2008 at 9:25pm.

x^2-3x+____

how do I figure out what goes there

- algebra -
**^Quen^**, Monday, February 25, 2008 at 11:25pmwell..I can't remember the formular for that one. But, you could figure it out by looking at equation.

x^2-3x+(?)

if you have to factor the equation, it will be like this: (x- ?) (x-?)

Because of the middle number is -3x and the (?) is positive, it has to be (-) something * (-) something. When you add those two, you have to get -3x. IF you multiply them, you 'll get positve (+) number.

So,

(x-2) (x-1)= x^2-x-2x+2

=x^2-3x+2

- algebra -
**Reiny**, Tuesday, February 26, 2008 at 12:06amSorry, but that is not correct

The question was to complete the square, so the first and last terms have to be perfect squares.

in general if the expression starts with 1x^2, take onehalf of the middle term coefficient and square that.

so 3/2 squared is 9/4

then x^2-3x+9/4 = (x-3/2)^2

- algebra -
**^Quen^**, Tuesday, February 26, 2008 at 4:45pmYea..I remembered now. Thanks 4 correcting !

- algebra -

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