math
posted by jose on .
solve using substitution
4x + 3y= 3
2x + y = 1

When we look at the second equation, we can transfer the term 2x to the other side of the equality. We get that:
2x+y = 1
<=> y = 12x
when we replace the y in the first equation by the value we just calculated, we get that:
4x + 3y= 3
<=> 4x + 3(12x)=3
<=> 4x  3 6x = 3
<=> 2x=0
<=> x=0
So, we find that x=0. When we replace this value for x in the equation we earlier found for y, we get that:
y=1(2*0)=1
So, we find that x=0 and y=1 
thanxz