Posted by **hokoslavia** on Monday, February 25, 2008 at 7:34pm.

how many atoms are present in 80.0 mol of zirconium?

- chemistry -
**Christiaan**, Monday, February 25, 2008 at 8:30pm
There is a constant in chemistry, know as Avogrado's number, which equals 6.023*10^23. This number equals the number of particles of a random material in exactly one mol of material. The mol is thus defined as containing exactly that number of particles. Now, since it's given that we have 80.0 mol of Zr, we just have to multiply this number with Avogrado's number to find the total amount of particles

=> amount of particles = 80*6.023*10^23

= 481.84*10^23

So there are roughly 481.84*10^23 atoms of 80 mol of Zr

- chemistry -
**opy**, Sunday, December 16, 2012 at 2:10pm
lol idk you tell me broo

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