Saturday

October 25, 2014

October 25, 2014

Posted by **Anonymous** on Monday, February 25, 2008 at 5:36pm.

The parachute on a race car that weighs 8042 N opens at the end of a quarter-mile run when the car is traveling 35 m/s. What net retarding force must be supplied by the parachute to stop the car in a distance of 1020 m? Answer in units of N.

- Physics still don't get it -
**Damon**, Monday, February 25, 2008 at 6:03pmm = weight in Newtons/ 9.81

Change in kinetic energy = average force * distance.

The change in KE is all the KE, since it stopped.

(1/2) m v^2 at the start = F * 1020

So F = (1/2) m v^2 / 1020

**Answer this Question**

**Related Questions**

Physics - Given: g=9.81 m/s square. The parachute on a race car that weighs 8042...

Physics - The parachute on a race car that weighs 8036 N opens at the end of a ...

Physics - The parachute on a race car of weight 8,810 N opens at the end of a ...

MELODY - The parachute on a race car of weight 8850 N opens at the end of a ...

physics help please! - A race car is one lap behind the lead race car when the ...

physics - A drag racer, starting from rest, speeds up for 402 m with an ...

physics - A drag racer, starting from rest, speeds up for 402 m with an ...

Physics - A drag racer, starting from rest, speeds up for 393 m with an ...

Physics - A drag racer, starting from rest, speeds up for 393 m with an ...

physics - A drag racer, starting from rest, speeds up for 384 m with an ...