Posted by **Jon** on Monday, February 25, 2008 at 4:08pm.

Write an equation in slope-intercept form for the line that passes through (3,5) and (-2,1).

y2-y1/x2-x1

1-5/-2-3

-4/-5= slope

y=mx+b

y=-4/-5(3)+b

-2=2.4+b

-4.4= y-intercept

y= -4/-5x+4.4 (answer)

- Math -
**drwls**, Monday, February 25, 2008 at 4:33pm
Rewrite the slope as m = 4/5. -4/-5 is the same thing but looks awkward.

y = (4/5) x + b

5 = [(4/5)*3] + b

5 = 12/5 + b

b = 13/5

y = (4/5)x + 13/5

- Math(here's what I did) -
**Jon**, Monday, February 25, 2008 at 5:08pm
Ok, we lmow that the slope is 4/5.

y=mx+b

y=4/5(3)+b

-2=2.4+b

subtract 2.4 from both sides

-4.4 which is how I got the y-intercept

y= 4/5x+4.4

13/5 = 2.6 not 4.4

- Math -
**drwls**, Monday, February 25, 2008 at 6:29pm
In solving for b, you took the x-value from one point (x=3) and, for y, you used the x value from the other point (x=-2) instead of y. You should have used y=5, as I did in my derivation. You have to use the x and y values of one known point to get the line to pass though that point.

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