Homework Help: Physics

Posted by Jenna on Monday, February 25, 2008 at 2:24pm.

Given: g=9.81 m/s square.
The parachute on a race car that weighs 8042 N opens at the end of a quarter-mile run when the car is traveling 35 m/s. What net retarding force must be supplied by the parachute to stop the car in a distance of 1020 m? Answer in units of N.

I have no idea what formula I should use or how to solve this problem.

Physics - bobpursley, Monday, February 25, 2008 at 3:06pm
retarding force*distance=Kineticenergyofcar
- Physics - Jenna, Monday, February 25, 2008 at 3:28pm
  so it would be:
  
  (retarding force)(1020m)= (1/2)(8042N)(35 m/s)
  and the retarding force= 137.98?
Physics - BLT, Sunday, February 19, 2012 at 3:51pm
You would first find the mass of the car using Weight = m*g

Once you have found the mass, you can solve for "a" in finding Fnet (Fnet= m*a) so (Fnet= 821*a)

Because Fnet= m a you can rearrange the equation and substitute this into the following equation:
(a)
V^2= Vi^2 + 2(Fnet/m)(X)
0 = (35^2) + 2(Fnet/821) (1020)

Therefore the Net Force will be approximately 493 N in the opposing direction. (Because it is an opposing force, the answer will come out negative)

Answer this Question

Related Questions

Physics still don't get it - Given: g=9.81 m/s square. The parachute on a ...
Physics - The parachute on a race car that weighs 8036 N opens at the end of a ...
Physics - The parachute on a race car of weight 8,810 N opens at the end of a ...
MELODY - The parachute on a race car of weight 8850 N opens at the end of a ...
physics - A drag racer, starting from rest, speeds up for 402 m with an ...
Physics - A drag racer, starting from rest, speeds up for 393 m with an ...
Physics - A drag racer, starting from rest, speeds up for 393 m with an ...
physics - A drag racer, starting from rest, speeds up for 384 m with an ...
physics - A drag racer, starting from rest, speeds up for 402 m with an ...
Physics - A drag racer, starting from rest, speeds up for 402 m with an ...

For Further Reading

First Name:
School Subject:
Answer: