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September 30, 2014

September 30, 2014

Posted by **Jenna** on Monday, February 25, 2008 at 2:24pm.

The parachute on a race car that weighs 8042 N opens at the end of a quarter-mile run when the car is traveling 35 m/s. What net retarding force must be supplied by the parachute to stop the car in a distance of 1020 m? Answer in units of N.

I have no idea what formula I should use or how to solve this problem.

- Physics -
**bobpursley**, Monday, February 25, 2008 at 3:06pmretarding force*distance=Kineticenergyofcar

- Physics -
**Jenna**, Monday, February 25, 2008 at 3:28pmso it would be:

(retarding force)(1020m)= (1/2)(8042N)(35 m/s)

and the retarding force= 137.98?

- Physics -
- Physics -
**BLT**, Sunday, February 19, 2012 at 3:51pmYou would first find the mass of the car using Weight = m*g

Once you have found the mass, you can solve for "a" in finding Fnet (Fnet= m*a) so (Fnet= 821*a)

Because Fnet= m a you can rearrange the equation and substitute this into the following equation:

(a)

V^2= Vi^2 + 2(Fnet/m)(X)

0 = (35^2) + 2(Fnet/821) (1020)

Therefore the Net Force will be approximately 493 N in the opposing direction. (Because it is an opposing force, the answer will come out negative)

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