Posted by **Anonymous** on Monday, February 25, 2008 at 10:01am.

A 50 kg pole vaulter falls from rest from a height of 5 meters onto a foam rubber pad. The pole vaulter comes to rest 0.22 seconds after landing on the pad. Calculate the athlete's velocity just before reaching the pad. Answer in m/s.

I am so confused about which formula to use with this problem. I tried doing it like this, but I don't know if it's right:

final velocity= initial velocity+(gravity)x(time)

final velocity= 0m/s + (-10m/s)(0.22s)

- Physical science -
**drwls**, Monday, February 25, 2008 at 10:12am
This is a trick question.

The time it takes to decelerate to zero depends upon the spring constant of the foam material, and they give you no information about that, so you cannot get the answer by using the decleration time. You have to get of from the height that he falls from, as follows

V = sqrt (2 g H) = 9.9 m/s

## Answer this Question

## Related Questions

- Physics - A 59 kg pole-vaulter falls from rest from a height of 5.5 m onto a ...
- Physics - A 55 kg pole vaulter falls from rest from a height of 5m onto a foam ...
- physics - A 85 kg pole-vaulter falls from rest from a height of 6.4 m onto a ...
- Physics - A 57.8 kg pole-vaulter falls from rest from a height of 5.4 m onto a ...
- physics - please help i cannot figure this out A 0.27 kg ball of dough is thrown...
- physics please help me - The pole vault landing pad at an Olympic competition ...
- please help dont know how to solve - The pole vault landing pad at an Olympic ...
- physics help - The pole vault landing pad at an Olympic competition contains ...
- physics - The pole vault landing pad at an Olympic competition contains what is ...
- physics - A surprising demonstration involves dropping egg from a third-floor ...