Posted by Vaughn on Monday, February 25, 2008 at 8:32am.
The rocket acquires all of the original momentum of the spaceship stops.
(M + m)V1 = m V2
2.5*10^6* 210 = 1350*V2
V2 = 3.89*10^5 m/s
This is an unrealistically high velocity for a rocket, or even a bullet-fired projectile. Furthermore, the spaceship fired a real rocket, most of the velcoty of the rocket would be acquired after release, and would not affect the velocity of the spacecraft. In that case, momentum conservation could not be used.
Related Questions
Physics - With the engines off, a spaceship is coasting at avelocity of +260m/s ...
physics - i need help figuring out what formaula to use for finding the final ...
math - The position function of a spaceship is below and the coordinates of a ...
physics - A space vehicle is coasting at a constant velocity of 20.5 m/s in the...
physics - A space vehicle is coasting at a constant velocity of 20.7 m/s in the...
physics - A space vehicle is coasting at a constant velocity of 22.5 m/s in the...
physics - A space vehicle is coasting at a constant velocity of 24.7 m/s in the...
physics - A space vehicle is coasting at a constant velocity of 21.1 m/s in the...
physics - A space vehicle is coasting at a constant velocity of 20.5 m/s in the...
physics - Model rocket engines are sized by thrust, thrust duration, and total ...
For Further Reading