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September 1, 2014

September 1, 2014

Posted by **Jessica** on Monday, February 25, 2008 at 3:50am.

sin(ax)cos(bx)dx

Could someone tell me what they got for an answer so I can check it to see if my answer is right.

My answer:

-1/2sinasinbx^2-1/3acosaxcosbx^3+ integral 1/3 a^2cosbx^3sinax..I'm not sure hot to find the integral of the last part.

- math -
**drwls**, Monday, February 25, 2008 at 6:58amI thnink the "generalizing" formula they expect you to use is the identity:

sin(ax) cos(by) = (1/2)[sin((a+b)x) + sin ((a-b)x)]

Those two terms can be easily integrated separately and added.

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