Posted by K on Monday, February 25, 2008 at 12:20am.
(note: cyclohexanol is a hexagon with an "-OH" attached off one of the carbons.)
cyclohexanol: OHCHCH_2CH_2CH_2CH_2CH_2 (I think that is sort of it, otherwise.)
Or just: C_6H_11-OH
saturated is based on how much you add.
color change => bromine is red-brown and when it reacts with a alkene it becomes colorless.
basically the reaction you have is a dehydration thus...what product do you form when you have a dehydration?
Potassium Permanganate can cleave bonds (during oxidation) DEPENDING on conditions such as heat or cold or basic or acidic conditions. you didn't mention any conditions so I can't say what will happen.
hope this helps
I can't help with the reaction though since usually it's written with molecules and mechanisms but not usually from..how you've written it.
basically I think your supposed to go and dehydrate the alcohol before you test it with
a) bromine in dichloromethane
b) potassium permanganate
I looked it up...can't believe I forgot this...( I did it)
basically the permanganate forms a precip when it reacts with a double bond (manganese oxide)
and the rxn of the bromine in dichloromethane is what I said above message (becomes colorless in the presence of a alkene)
However if it is as you say a alchohol with a test like these..basically I don't think anything would happen...
The experiment is on dehydration of an alkene & then to test it to see if it is "unsaturated" or "saturated", which I really should have specified!!...sry!!!!
For this exp. we are to only have like 3 drops of the Br in CH2Cl2 & add in 1-2 drops of cyclohexene (the product from Cyclohexanol)...then see what happens & attempt to write an equation...which is really that part that I am not sure on whatsoever!
There is no reaction between cyclohexanol and bromine in dichloromethane. The solution will remain coloured.
With cyclohexene the bromine adds across the double bond and the solution will become colourless. The predominant product is trans-1,2 dibromocycolhexane as the bromine atoms add from opposite side of the ring.
CH=CHCH2CH2CH2CH2 + Br2 =
|______________|
CHBr-CHBrCH2CH2CH2CH2
|__________________|
Sorry can't draw rings on here!
Hope this helps.
Thank you both of you for your help.
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