Posted by **Carlo** on Sunday, February 24, 2008 at 10:38pm.

Hi, I was wondering if you could possibly help me with this chem question.

For the relatively slow decomposition of NOCL into NO and Cl2 according to the reaction below, it is known that the reaction is second order w/ respect to NOCl and that after 23.4 minutes that 75% of NOCl is decomposed when the initial concentration of NOCl is 0.0732 M. How long (in minutes) would it take until 35.8% of the NOCl has decayed?

2 NOCl ---> 2 NO + Cl2

i think i have to use the integrated law but other than that how would i work this out? Thank you.

1/[A]=(kt + 1)/A null

- Ap Chemistry -
**DrBob222**, Sunday, February 24, 2008 at 11:36pm
For a second order reaction, the equation is

(1/A) - (1/Ao) = akt

I think you have Ao, A, a, and t (23.4 min) so you can solve for k (at 75% decomposition).

Then use k in the revised equation. You will have k, A, Ao (for 35.8% decomposition) and a, and you can solve for t. Check my thinking.

## Answer This Question

## Related Questions

- chem 12 - consider the following equilibrium 2NOCl(g)--- 2 NO(g) + Cl2(g) ...
- Chem II - 2.5 mol NOCl(g) was placed in a 2.50 L reaction vessel at 400 degrees ...
- chemistry - Calculate Hrxn for the reaction below. 2 NOCl(g) N2(g) + O2(g) + Cl2...
- chemistry - I have been at this question for at least three hours now. Consider ...
- Chemistry - The following reaction exhibits the rate law: Rate = k[NO2]^2[Cl2]. ...
- Chemistry - At 35 degrees Celcius, K = 1.6x10^-5 for the reaction: 2NOCl<--&...
- Chemistry(Please help, thank you!) - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl...
- Chemistry - 0.500 moles of NOCl is placed in a 1.00L vessel at 700K,and after ...
- chemistry - Using this data, 2 NO(g) + Cl2(g) == 2 NOCl(g) Kc = 3.20 X 10-3 NO2(...
- chemistry - Given the following thermochemical equations, NO(g) + (1/2) Cl2(g...

More Related Questions