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January 29, 2015

January 29, 2015

Posted by **jonathan** on Sunday, February 24, 2008 at 9:16pm.

- trig -
**Reiny**, Sunday, February 24, 2008 at 9:24pmlooks like a straightforward application of the cosine law.

120^2 = 90^2 + 135^2 - 2(90)(135)cosß

where ß is the angle between them

- trig -
**Damon**, Sunday, February 24, 2008 at 9:24pmShip A went 30 * 3 = 90 km

Ship B went 45 * 3 = 135 km

So we have a triangle with legs of 90 and 135 and an opposite side of 120

Use the law of cosines

120^2 = 90^2 + 135^2 - 2*90*135 cos T

solve for T

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