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April 2, 2015

Posted by **maryam** on Sunday, February 24, 2008 at 8:06pm.

M(n)=(n^3-48n+1100)/200

The producer, your boss, comes in and asks you to prepare a report on the funding needs for Radio and Television advertising in the days between the media blitz and the release, highlighting the rate at which spending goes up or down each day. In particular he seems interested in the rate at which spending will change in the 'th day. To estimate this,using your formula, calculate the average rate of change for each of the following intervals (in 100,000 dollars per day):

Average rate of change on [0,1]:

Average rate of change on [1,2]:

Average rate of change on [2,3]:

Average rate of change on [3,4]:

Average rate of change on [4,5]:

Average rate of change on [5,6]:

Average rate of change on [6,7]:

Average rate of change on [7,8]:

Average rate of change on [8.9]:

Average rate of change on [9,10]:

Why was the manager interested in the 'th day?

a)NO reason

b)Spending starts increasing day after day

c)the day is peak of expenditures

d)Spending starts decreasing day after day

Your best estimate for the instantaneous rate of change at the 4'th day:

please help with this questions...i really dont get how to slve!

mary

- calculus -
**Damon**, Sunday, February 24, 2008 at 9:16pmWell they say estimate so I would not calculate the cubic equation for each day and subtract. I would use the derivative.

Since they want the average rate of change between 0 and 1 for example, I think it appropriate to use the rate of change at the derivative at 0 and the derivative at 1 and average them for 0 - 1

Of course we must get that derivative

M(n)=(n^3-48n+1100)/200

200 M(n) = n^3 - 48 n + 1100

200 dM/dt = 3 n^2 -48

so

rate n = dM/dt = (3 n^2 -48)/200

calculate that at

n = 0

n = 1

n = 2

n = 3 etc

then

rate 0 - 1 = (1/2)( rate 0 + rate 1)

by the way the maximum spending will be when dM/dt = 0

3 n^2 - 48 = 0

n^2 = 16

n = 4

That is why they want you to calculate M there and that is why the boss wants to know these rates.

- calculus -
**Damon**, Sunday, February 24, 2008 at 9:20pmBy the way, I would personally program a spreadsheet to do those numbers, but a fancy programable calculator would do it pretty fast.

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