How many moles of Carbon dioxide are produced from the decompostion of 1.45 grams of Aluminum Carbonate?

reaction balanced equation.

Al2C3 + O2 ----> CO2 + Al3

therefore

3Al2C3 + 9O2 = 9CO2 + 2Al3

so try to find the mass of CO2 from the equation, then n= m/M

Which of the following is NOT true about the thermodynamic standard state?

A. A gas is in its standard state when its pressure is 1.00 atm and its temperature is 25C.
B. An aqueous solution is in its standard state at a concentration of 1.00 M.
C. A pure liquid is in its standard state at 25C and a vapor pressure of 1.00 atm.
D. A solid is in its standard state when the atmospheric pressure is 1.00 atm and the temperature is 25C.
E. All of these are true.
I thought that the answer would be D.

The balanced equation is

Al2(CO3)3 ==> Al2O3 + 3CO2

Step 1. Convert 1.45 g Al2(CO3)3 to mols.
Step 2. Using the coefficients in the balanced equation, convert mols Al2(CO3)3 to mols CO2.
Post your work if you get stuck.

You stand a better chance of getting an answer if you post your own guestion and don't piggy back on another one.

To determine the number of moles of carbon dioxide produced from the decomposition of aluminum carbonate, we need to know the balanced chemical equation for the reaction and use the molar masses of the compounds involved.

The balanced chemical equation for the decomposition of aluminum carbonate (Al2(CO3)3) is:
2 Al2(CO3)3 -> 4 Al + 3 CO2

From the equation, we can see that for every 2 moles of aluminum carbonate decomposed, 3 moles of carbon dioxide are produced.

Step 1: Calculate the molar mass of aluminum carbonate (Al2(CO3)3).
Aluminum (Al) has an atomic mass of 26.98 g/mol.
Carbon (C) has an atomic mass of 12.01 g/mol.
Oxygen (O) has an atomic mass of 16.00 g/mol.

Molar mass of aluminum carbonate:
2(26.98 g/mol) + 3(12.01 g/mol) + 3(16.00 g/mol) = 233.98 g/mol

Step 2: Convert the given mass of aluminum carbonate to moles.
Given mass = 1.45 grams

Number of moles of aluminum carbonate:
1.45 g / 233.98 g/mol = 0.0062 mol

Step 3: Use the mole ratio from the balanced chemical equation to find the number of moles of carbon dioxide produced.
From the equation: 2 moles Al2(CO3)3 -> 3 moles CO2

Number of moles of CO2 produced:
0.0062 mol Al2(CO3)3 x (3 mol CO2 / 2 mol Al2(CO3)3) = 0.0093 mol

Therefore, from the decomposition of 1.45 grams of aluminum carbonate, approximately 0.0093 moles of carbon dioxide are produced.