the fuel methanol(CH3OH) is made by the reaction of carbon monoxide and hydrogen.
a) write the balanced chemical reaction
b)how many grams og hydrogen are needed to produce 45.0 grams of methanol?
Equation by Amanda is ok.
part b is not.
Convert 45.0 g CH3OH to mols. # mols = grams/molar mass.
Convert mols CH3OH to mols H2 using the coefficients in the balanced equation.
Convert mols H2 to grams H2 remembering that grams = mols H2 x molar mass H2.
Post your work if you get stukc.
hip
a) To write the balanced chemical reaction for the formation of methanol (CH3OH) from carbon monoxide (CO) and hydrogen (H2), we need to make sure that the number of atoms on both sides of the equation are the same. Here is the balanced chemical reaction:
CO + 2H2 -> CH3OH
In this reaction, one molecule of carbon monoxide reacts with two molecules of hydrogen to produce one molecule of methanol.
b) To determine the number of grams of hydrogen needed to produce 45.0 grams of methanol, we need to use stoichiometry. Stoichiometry is the calculation of quantities in chemical reactions based on the balanced equation.
The molar mass of methanol (CH3OH) is 32.04 g/mol. From the balanced equation, we can see that one molecule of methanol requires two molecules of hydrogen. Since the molar mass of hydrogen (H2) is 2.02 g/mol, we can calculate the amount of hydrogen needed.
First, we need to calculate the number of moles of methanol:
Moles of methanol = Mass of methanol / Molar mass of methanol
Moles of methanol = 45.0 g / 32.04 g/mol
Moles of methanol ≈ 1.403 mol
Since the balanced equation shows that 1 mole of methanol requires 2 moles of hydrogen, we can calculate the moles of hydrogen needed:
Moles of hydrogen = Moles of methanol × 2
Moles of hydrogen = 1.403 mol × 2
Moles of hydrogen ≈ 2.806 mol
Finally, we can calculate the mass of hydrogen needed:
Mass of hydrogen = Moles of hydrogen × Molar mass of hydrogen
Mass of hydrogen = 2.806 mol × 2.02 g/mol
Mass of hydrogen ≈ 5.67 g
Therefore, approximately 5.67 grams of hydrogen are needed to produce 45.0 grams of methanol.
CO + 2H2 = CH3OH
2mol 1mol
?gr 45gr
45 x 2 = 90 grams
hope i got it right for you