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January 30, 2015

January 30, 2015

Posted by **Jon** on Sunday, February 24, 2008 at 6:49pm.

Solve: 3+/2y-1/>=1. Graph the solution set on a number line.

The number line I have is:

-5 -4 -3 -2 -1 0 1 2 3 4 5 6

First solution:

3+2y-1>=1

2y-4>=1

2y>=5

y>=5/2

I'm stuck b/c I had to correct the first part. I had a whole different answer. The graph for this would be an open circle between 2 and 3 and the arrow going right.

- Math -
**Damon**, Sunday, February 24, 2008 at 7:52pm|2y-1| = +(2y-1) if y >1/2

|2y-1| = -(2y-1) if y <1/2

so do the whole problem first for y >1/2

3 + 2y - 1 >/= 1

2 + 2y >/= 1

1+y >/= 1/2

y >/= -1/2

so this is true if y >1/2

now do the whole problem for y<1/2

3 - 2y +1 - 1 >/= 1

3 - 2y >/= 1

-2y >/= -2

y </= 1

so it is true for any y greater than 1/2 and for any y less than 1 and so the entire real number line

Try some spots

y = 0 yes

y = -1 yes

y = +1 yes

y = 1/2 yes

y = -1/2 yes etc etc etc

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