Posted by Anonymous on Sunday, February 24, 2008 at 6:41pm.
You want F DOT D (I am using capital for vector) = |F||D| cos T
where T is the angle between them.
dot product = scalar product = FxDx + FyDy
= 4*3 + 1*10 = 12+10 = 22
Now do that one other way
|F| = sqrt(4^2+1^2) = sqrt(17)
|D| = sqrt(3^2+10^2) = sqrt (109)
angle F to x axis = tan^-1 (1/4) =14 deg
angle D to x axis = tan^-1 (10/3)=73.3 deg
so T = 73.3 - 14 = 59.3
cosT = .5105
so
W = |F||D| cos T = 21.97 = 22 to our sig figs
check
b)
F = 2i
d = 5i + 6j
W = 2*5 + 0*6
W = 10
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