Posted by Anonymous on Sunday, February 24, 2008 at 6:41pm.
I forgot how to do the following, so I'm not sure if they're correct or not:
Find the work done by a force "F" that causes a displacement "d".
i and j = unit vectors
a)
F = 4i + j
d = 3i + 10j
W = (4i + j)(3i + 10j)
W = 12i^2 + 40ij + 3ij + 10j^2
W = 12(1) + 40(0) + 3(0) + 10(1)
W = 22
b)
F = 2i
d = 5i + 6j
W = (2i)(5i + 6j)
W = 10i^2 + 12ij
W = 10(1) + 12(0)
W = 10

Math: Vectors  Damon, Sunday, February 24, 2008 at 7:29pm
You want F DOT D (I am using capital for vector) = FD cos T
where T is the angle between them.
dot product = scalar product = FxDx + FyDy
= 4*3 + 1*10 = 12+10 = 22
Now do that one other way
F = sqrt(4^2+1^2) = sqrt(17)
D = sqrt(3^2+10^2) = sqrt (109)
angle F to x axis = tan^1 (1/4) =14 deg
angle D to x axis = tan^1 (10/3)=73.3 deg
so T = 73.3  14 = 59.3
cosT = .5105
so
W = FD cos T = 21.97 = 22 to our sig figs
check 
Math: Vectors  Damon, Sunday, February 24, 2008 at 7:31pm
b)
F = 2i
d = 5i + 6j
W = 2*5 + 0*6
W = 10