Posted by **Jon** on Sunday, February 24, 2008 at 6:31pm.

1)Solve 3+2(1-x)>6 or 2x+14<=8. Graph the solution set on a number line.

The number line I'm working with is:

-4 -3 -2 -1 0 1

First solution:

3+2-2x>6

5-2x>6

-2x>1

x> -1/2

for the graph, I have an open circle between 0 and 1 and the arrow going right.

Second solution:

2x+14<=8

2x<= -6

x<= -3

for the graph, I have a closed circle on the -3 and the arrow going left.

- Math -
**Amanda**, Sunday, February 24, 2008 at 7:45pm
seem right to me.

- Math -
**Reiny**, Sunday, February 24, 2008 at 8:18pm
You made an error in the first part.

for the first one you had

-2x>1

x> -1/2

when you divide by a negative, the inequality sign has to be reversed, so it is

x < -1/2

so that would be an open circle at -1/2 and the line going to the left.

since your relations are joined with OR and the second one is x < -3

the actual solution would be the first graph above.

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