Posted by Jon on Sunday, February 24, 2008 at 6:31pm.
1)Solve 3+2(1x)>6 or 2x+14<=8. Graph the solution set on a number line.
The number line I'm working with is:
4 3 2 1 0 1
First solution:
3+22x>6
52x>6
2x>1
x> 1/2
for the graph, I have an open circle between 0 and 1 and the arrow going right.
Second solution:
2x+14<=8
2x<= 6
x<= 3
for the graph, I have a closed circle on the 3 and the arrow going left.

Math  Amanda, Sunday, February 24, 2008 at 7:45pm
seem right to me.

Math  Reiny, Sunday, February 24, 2008 at 8:18pm
You made an error in the first part.
for the first one you had
2x>1
x> 1/2
when you divide by a negative, the inequality sign has to be reversed, so it is
x < 1/2
so that would be an open circle at 1/2 and the line going to the left.
since your relations are joined with OR and the second one is x < 3
the actual solution would be the first graph above.