Posted by Anonymous on Sunday, February 24, 2008 at 2:06pm.
For equilibrium on the ramp, the sum of the forces parallel to the ramp must be 0. For a ramp inclined 30 degrees, the force component of the box parallel to the ramp is 215N * sin(30).
The frictional force is given as 27N up the ramp. Solve for the additional force up the ramp for equilibrium:
F=needed force for equilibrium
positive is up the ramp
-(215N * sin(30)) + 27N + F = 0
The value for F here is a force parallel to the ramp. If the equilibrium force is applied at an angle 40 degrees to the ramp, then solve for the value which has a component parallel to the ramp equal to the needed force above.
F2=force applied at 40 degrees to ramp
F = F2 * cos(40)
F was found above, solve for F2
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