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January 25, 2015

January 25, 2015

Posted by **Anonymous** on Sunday, February 24, 2008 at 2:06pm.

Textbook Answer: 80.5 N and 105 N

Please explain thoroughly!

- Math: Dot Product -
**Quidditch**, Sunday, February 24, 2008 at 2:53pmFor equilibrium on the ramp, the sum of the forces parallel to the ramp must be 0. For a ramp inclined 30 degrees, the force component of the box parallel to the ramp is 215N * sin(30).

The frictional force is given as 27N up the ramp. Solve for the additional force up the ramp for equilibrium:

F=needed force for equilibrium

positive is up the ramp

-(215N * sin(30)) + 27N + F = 0

The value for F here is a force parallel to the ramp. If the equilibrium force is applied at an angle 40 degrees to the ramp, then solve for the value which has a component parallel to the ramp equal to the needed force above.

F2=force applied at 40 degrees to ramp

F = F2 * cos(40)

F was found above, solve for F2

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