Posted by **jimmy** on Sunday, February 24, 2008 at 2:58am.

find the real number solutions of the equation.

w^4+w^3-w=1

could you please show step by step..thank you

- algebra -
**newbie**, Sunday, February 24, 2008 at 3:35am
is it only 1 b/c if u substitute 1 into w, it'll equal to 1

- algebra -
**mk-tintin**, Sunday, February 24, 2008 at 3:43am
w^4+w^3-w=1

w^4+w^3-w-1=0

(w-1)(w^3+2w^2+2w+1)=0

(w-1)(w+1)(w^2+w+1)=0

so real solutions are 1 and -1

complex solutions are 1 -1 j j^2 with j=exp(2Pi/3)

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