Posted by jimmy on Sunday, February 24, 2008 at 2:58am.
find the real number solutions of the equation.
w^4+w^3w=1
could you please show step by step..thank you

algebra  newbie, Sunday, February 24, 2008 at 3:35am
is it only 1 b/c if u substitute 1 into w, it'll equal to 1

algebra  mktintin, Sunday, February 24, 2008 at 3:43am
w^4+w^3w=1
w^4+w^3w1=0
(w1)(w^3+2w^2+2w+1)=0
(w1)(w+1)(w^2+w+1)=0
so real solutions are 1 and 1
complex solutions are 1 1 j j^2 with j=exp(2Pi/3)
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