Posted by Shirley on Saturday, February 23, 2008 at 8:42pm.
There are two ways to do this kind of problem. One is to use calculus, which leaves you with the equation
2I - 30 = 0, leading right away to I = 15. The other way, which does not require calculus, is to use the method of "completing the square". That is what was done in the example you posted. When the equation
P = 240I-8I^2 is rewritten
I^2 - 30 I +(30/2)^2 = -P/8 + 225
= (I-15)^2 , or
P/8 = 225 -(I - 15)^2
you see right away that the maximum value of P is obtained when I = 15.
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