Posted by **megan** on Saturday, February 23, 2008 at 6:34pm.

the relationship b/w the distance d, in feet, required to stop a vehicle and s, the speed in miles per hour that the vehicle was traveling, is given by the equation

d=0.0155s(squared)/f

f represents the coefficient of friction b/w the tires and the road

*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.

i did 205= 0.0155s(squared)/0.3...idk how to solve this

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