Tuesday

March 31, 2015

March 31, 2015

Posted by **megan** on Saturday, February 23, 2008 at 6:34pm.

d=0.0155s(squared)/f

f represents the coefficient of friction b/w the tires and the road

*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.

i did 205= 0.0155s(squared)/0.3...idk how to solve this

- algebraic reasoning -
**Damon**, Saturday, February 23, 2008 at 7:17pm205 = 0.0155 s^2 / 0.3

multiply both sides by 0.3

61.5 = 0.0155 s^2

divide both sides by 0.0155

3968 = s^2

take the square root of both sides

63 miles per hour

**Answer this Question**

**Related Questions**

math - For a motor vehicle traveling at r miles per hour, the distance d in feet...

algebra - For a motor vehicle travelling at r miles per hour, the distance d in ...

physics - how much would a stationary vehicle have to accelerate in order for it...

Math - The distance require to stop a car varies directly as the square of its ...

math - a vehicle uses 1 tablespoon of gasoline to drive 125 yard how many miles ...

Physics Conservation of Energy - A car traveling at 20 miles/hour stops in a ...

Calculus - The total stopping distance T of a vehicle is T=2.5x+0.5x^2 where T ...

math - Assume that stopping distance of a van varies directly with the square of...

Help!...Math... - Two cars leave town going opposite directions. One car is ...

statistics - A study performed by Bridge Ratings found that in 2006, 58% of ...