Posted by **megan** on Saturday, February 23, 2008 at 6:34pm.

the relationship b/w the distance d, in feet, required to stop a vehicle and s, the speed in miles per hour that the vehicle was traveling, is given by the equation

d=0.0155s(squared)/f

f represents the coefficient of friction b/w the tires and the road

*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.

i did 205= 0.0155s(squared)/0.3...idk how to solve this

## Answer This Question

## Related Questions

- math - For a motor vehicle traveling at r miles per hour, the distance d in feet...
- algebra - For a motor vehicle travelling at r miles per hour, the distance d in ...
- physics - how much would a stationary vehicle have to accelerate in order for it...
- Math - The distance require to stop a car varies directly as the square of its ...
- math - a vehicle uses 1 tablespoon of gasoline to drive 125 yard how many miles ...
- Math - First vehicle is traveling at 50 miles per hour. Second car is traveling ...
- Physics Conservation of Energy - A car traveling at 20 miles/hour stops in a ...
- Calculus - The total stopping distance T of a vehicle is T=2.5x+0.5x^2 where T ...
- Help!...Math... - Two cars leave town going opposite directions. One car is ...
- math - Assume that stopping distance of a van varies directly with the square of...

More Related Questions