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August 27, 2014

August 27, 2014

Posted by **logan** on Saturday, February 23, 2008 at 6:17pm.

-2v^6=16

3s^4+15s^2-72=0

3c^7=81c^4

3q^4+3q^3=6q^2+6q

any help would be appreciate...thank you!!

- algebra 2 (#3 of 4) -
**drwls**, Saturday, February 23, 2008 at 7:48pmRewrite as 3c^4(c^3 -27) = 0

This is true if either c=0 or c^3 = 27

27 is the cube of 3, so c=3 is the other solution.

- algebra 2 (#3 of 4) -
**logan**, Saturday, February 23, 2008 at 8:35pmcan you help me with the other three!!

- algebra 2 (#3 of 4) -

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