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March 30, 2015

March 30, 2015

Posted by **Anonymous** on Saturday, February 23, 2008 at 6:10pm.

++++Textbook Answer for Question 15: 108.3 N

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14) A crate is being dragged up a ramp by a 125 N force applies at an angle of 40 degrees to the ramp. Find the magnitude of the force in the direction of motion (Answer is 95.8 N).

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+++++Please provide a step by step solution to this problem (question 15)! I really don't know what I'm doing! I know the answer, but I don't know how to get that answer! Thank you.

- Math: Applications of Dot Product -
**Damon**, Saturday, February 23, 2008 at 6:45pm14)

F vector at 40 degrees to motion direction Call Unit vector up ramp parallel to ramp Au.

The component of F in the direction of Au is

F dot Au = |F| * 1 cos (40) = 125(.766) = 95.8 Newtons

15) The 125 N is at 20+40 = 60 degrees from horizonal, so at 30 degrees from vertical

125 cos 30 = 108.3 N

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